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Y(x,t) = A*sin(kx)cos(omega*t).
Consider a string of length two meters stretched between two supports and vibrating according to the above equation. Let k = 2pi/4 m-1, omega = 60 s-1, and A = 6 cm. How many nodes and how many anti nodes are present?
Consider the sound pipe shown, with one end closed and one open (the book calls this a stopped pipe). Where are the amplitude nodes and antinodes for the lowest frequency (longest wavelength) normal mode of oscillation?
For a normal mode oscillation, the distance between (amplitude) nodes is
1/4 wavelength
1/2 wavelength
1 wavelength
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