Student Responses to Centripetal Force Questions:

9/2/96,1801 sName,BF
sSection,M3/4a
Q1,To slow down the horse, let more slack in the rope, so that the horse has a farther distance to run.
Q2,F = ma

7500=1000a
a=7.5m/s
Q3,b
1D,SUBMIT HOMEWORK

9/3/96,2005 sName,NS
sSection,M3A
Q1,I would set up a wooden pole between myself and the horse. If I leaned against the pole, I would have stability even as the horse rotates around me.
Q2,If the horse weighed about 2000 kg, the horse would have to accelerate at 16.54 m/s%5E2.
Q3,b
1D,SUBMIT HOMEWORK

9/3/96,2007 sName,MF
sSection,M3A
honor,on
Q1,One way to slow the horse without moving would be to lengthen the amount of rope that the horse is connected by.
Q2,Using a mass of 450 kg, the acceleration would have to be 73.5 m/s%5E2, so with a 10 meter rope, the horse would have to go 27.1 m/s.
Q3,b
1D,SUBMIT HOMEWORK

9/3/96,2128 sName,LB
sSection,M 1
honor,on
Q1,shorten the rope
Q2,if the horse weighs 360kg

it would take abour 14 m/s at a ten foot
rope
Q3,c
1D,SUBMIT HOMEWORK

9/3/96,2200 sName,TA
sSection,M1
Q1,Pull the rope in closer to your body.
Q2,33km/hour

radius of rope: 10 m
mass of horse:300 kg
Q3,a
1D,SUBMIT HOMEWORK

9/3/96,2201 sName,??
sSection,
honor,on
Q1,Change the length of the rope.
Q2,7501=400kg*a
7501/400 = 18.7 m/s%5E2

Q3,c
1D,SUBMIT HOMEWORK

9/3/96,2222 sName,JD
sSection,M1/2A
honor,on
Q1,You could

a. shoot him

b. pull on the rope to shorten it and
bring the horse closer to you. He
should slow down because if he
Tdoesn't, he will have to run a tight
circle at a high velocity, and he will
not be able to physically do that.
Q2,The horse would have to be moving
66 m/s.
Q3,d
1D,SUBMIT HOMEWORK

9/3/96,2241 sName,MH
sSection,m1
honor,on
Q1,Technically if the horst keeps going then you can't slow it down without moving. Otherwise I would shoot the horse. This is the only other way to change the direction of the velocity.
Q2,165m/s
Q3,b
1D,SUBMIT HOMEWORK

9/3/96,2255 sName,BL
sSection,M3A
honor,on
Q1,You would lengthen the rope. The horse
would then be moving a longer distance.
Q2,The horse would have to run about
2 meters per second.(This is based on
the assumption that the horse is tied
to a 3 meter length of rope.
Q3,c
1D,SUBMIT HOMEWORK

9/3/96,2322 sName,RH
sSection,M1A
honor,on
Q1,In order to get the horse to slow down, you would need to put some slack in the rope
Q2,A horse weighing 454 kg would have to accelerate at 72.85 m/s%5E2 in order to produce 33076 N of preasure.
Q3,c
1D,SUBMIT HOMEWORK

9/3/96,2350 sName,DB
sSection,M1
honor,on
Q1,If you change the length of the rope, the horse has to run a different distance. So shorten the rope and the horse will slow down.
Q2,The horse, of mass 500 Kg, would have to run 15 m/s to break the rope.
Q3,c
1D,SUBMIT HOMEWORK

9/4/96,0015 sName,RN
sSection,M3A
honor,on
Q1,The only possible way to stop the horse
is to turn the opposite way the horse turns and then the forces will cancel each other out.
Q2,I don't have the slightest clue of how to work this problem.
Q3,c
1D,SUBMIT HOMEWORK

9/4/96,0050 sName,JM
sSection,M3A
honor,on
Q1,You can slow the horse down by shortening the length of rope and tightening the circular path of the horse. It therefore has a smaller space to move in and must eventually slow down before all the rope is pulled in.
Q2,If the horse weighed 700lbs, it would take an acceleration of 10.7m/s%5E2 to break the rope. The velocity to attain this acceleration would depend on the radius of the circle which is not given.
Q3,b
1D,SUBMIT HOMEWORK

9/4/96,0756 sName,RG
sSection,m1a
honor,on
Q1,Increase strain on rope.
Q2,With a 272kg horse it would have to run greater than 27.5m/s
Q3,c
1D,SUBMIT HOMEWORK

9/4/96,0807 sName,DM
sSection,m3-4
Q1,If you pull on the rope, the horse will slow down.
Q2,66.2 meters per second squared. F=ma
around 500kg
Q3,c
1D,SUBMIT HOMEWORK

9/4/96,0810 sName,RH
sSection,M3A
honor,on
Q1,I can't think of any way unless you
throw a rock at the horse or maybe
break its leg, or you could yell 'whoa'
horse.
Q2,The horse would have to accelerate with
about 66.15 m/s%5E2.
Q3,c
1D,SUBMIT HOMEWORK

9/4/96,0821 sName,KB
sSection,M1A
honor,on
Q1,Pull the rope tighter, so that the horse runs in a smaller circle.
Q2,48.6 m/s
Q3,c
1D,SUBMIT HOMEWORK

9/4/96,0831 sName,JH
sSection,M1A
honor,on
Q1,If you pull down on the rope it will cause more stress on the horse.
Q2,If the horse weighed 300 lbs it would have to run 25 miles/hour.
Q3,c
1D,SUBMIT HOMEWORK

9/4/96,1054 sName,TB
sSection,M3A
honor,on
Q1,If you tighten the rope the horse will speed up.
but if you loosen the rope he/she
may slow down.
Q2,w = 2000lb
F = 7500lb
a = 3.37

Q3,b
1D,SUBMIT HOMEWORK

9/4/96,1227 sName,CM
sSection,m1/2
Q1,If you let line out the horse will have to run further and thus exhausting the out- of-shape horse and slow it down faster.
Q2,using F=MA and an approximate mass of the horse to be 1,000 lbs, i came up with an acceleration of 7.5 ft per second squared.
Q3,c
1D,SUBMIT HOMEWORK



9/4/96,2041 sName,CM
sSection,110z M3a
honor,on
Q1,In class today we discussed this and came to the conclusion that the only way to slow the horse down is to make the radius between you and the horse smaller, so pull the rope in.
F=m(v%5E2/r)
Q2,F=33075 N
m= 60 kg
v=
r= 1m

F=m*(v%5E2/r)
v= 23.4 m/s
Q3,b
1D,SUBMIT HOMEWORK



9/4/96,2050 sName,?C
sSection,m1
honor,on
Q1,Letting out line will reduce the horses acceleration.
Q2,Really fast, acceleratoin over 10 mph/s*s
Q3,b
1D,SUBMIT HOMEWORK



9/5/96,2022 sName,CL
sSection,M1/M2
honor,on
Q1,By shortening the rope, in order for the horse to make the same number of revolutions around you, it will have to slow down.

Q2,The horse would have to exert a force greater than 33075 N. So, using the mass of the horse as 454 kg(1,000 lbs) and using the equation F=ma we can find the acceleration.

33075N = 454kg * a
a = 72.9 m/s%5E2

Q3,b
1D,SUBMIT HOMEWORK



9/5/96,2126 sName,ND
sSection,M-3/4
honor,on
Q1,You can do it by shortening the rope.
By doing this you are changing the radius
to a smaller number therefore the velocity
needs to slow down.
Q2,THe horse would have to run 10 meters
per second


Q3,b
1D,SUBMIT HOMEWORK



9/5/96,2205 sName,JB
sSection,M1/2 Dr. Patterson
honor,on
Q1,There is not really a way to make the horse slow down his speed, but relative to my position it would appear that the horse is slowing down if I made the length of the rope longer.
Q2,The horse would have to be going about 6.7 m/s%5E2.
Q3,b
1D,SUBMIT HOMEWORK



9/6/96,0020 sName,JK
sSection,M1A
honor,on
Q1,By lengthening the rope and increasing the size of the circle around you, you will slow down the horse without moving from your spot.
Q2,F = mv%5E2/r
F = 33075 N
m = 500 kg
r = 10 m

v = 25.7 m/s
Q3,d
1D,SUBMIT HOMEWORK



9/6/96,0912 sName,ZJ
sSection,M1a
honor,on
Q1,If you decrease the radius, the horse would complete a circle in a smaller amount of time, but he would be going slower because if the radius decreased and speed remained constant or speeded up, the acceleration would also have to rise. This rise in acceleration would make it impossible for the horse to keep running.
Q2,Assuming a 10 meter radius and the horse weighing 1000 kg. 18.2 m/s
Q3,b
1D,SUBMIT HOMEWORK



9/6/96,1207 sName,RK
sSection,M3A
honor,on
Q1,Because the horse has control over his own speed the laws of physics really don't apply here, but if I were swinging the horse I would let out more rope to slow him down. In this case I would have to pull him over or knock him down to affect his speed.
Q2,A big horse weighing 454 N would have to accelerate to 73 m/sec2 in order to break the rope. In other words the horse would have to be moving really fast, so he could notbreak the rope.
Q3,c
1D,SUBMIT HOMEWORK



9/6/96,1226 sName,RK
sSection,M3A
honor,on
Q1,pull
hit

Q2,A 2,000 lb car plus the engine which probably weighs aroung 15,000 lbs would accellerate at 13.7 m/sec2.
Q3,e
1D,SUBMIT HOMEWORK



9/6/96,1245 sName,??
sSection,
Q1,The first equation determines the time of flight because it determines the height of the ball and how long before it hits the earth.
Q2,I think a reasonable velocity for a runner in a 3m distance is about 5m/s. Therefore, a good minimum length for the pool would be 20m.
Q3,vv=0
1D,SUBMIT HOMEWORK