Q1,There can be an electric field at a point where there is no charge because there are electrons and protons present but there charges balance each other out. There can not be a charge at a place where there is no field because there are no protons or electrons present and without electrons and protons present there is no electric field.
Q2,The maximum value of Q would be very small a rough estimate might be around zero like 10^-12 C. Again the number would have to be very small.
Q3,d
Comments,
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Q1,Yes. There can be an electric field where there is no charge. Some charge at some other location can produce an electric field at this point. No. Any time there is a charge it creates an electric field in its vicinity.
Q2,Assume the charges are held at a distance d and the maximum force that can be sustained by the hands F. And by Coulomb's law, the maximum charge is given by F=QQ/4piedd and Q= 2d SQRT(pie)
Q3,c
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Q1,Yes, there can be an electric field at a point with no charge. But there will be no force from it untill a point with a charge is there. No, there will always be a field with a charge.
Q2,Well, in order to repel the charges would have to be like (both either positive or negative). This charge would have to be very small probably in the nano coulombs, because 1 meter apart is not very far for the equation F=k q1 q2/rxr.
Q3,c
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Q1,Yes, there can be an electric field at a point with no charge. But there will be no force from it untill a point with a charge is there. No, there will always be a field with a charge.
Q2,Well, in order to repel the charges would have to be like (both either positive or negative). This charge would have to be very small probably in the nano coulombs, because 1 meter apart is not very far for the equation F=k q1 q2/rxr.
Q3,c
Comments,
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Q1,Yes, there can be an electric field at a point with no charge. But there will be no force from it untill a point with a charge is there. No, there will always be a field with a charge.
Q2,Well, in order to repel the charges would have to be like (both either positive or negative). This charge would have to be very small probably in the nano coulombs, because 1 meter apart is not very far for the equation F=k q1 q2/rxr.
Q3,c
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Q1,Yes, there can be an electric field at a point with no charge. But there will be no force from it untill a point with a charge is there. No, there will always be a field with a charge.
Q2,Well, in order to repel the charges would have to be like (both either positive or negative). This charge would have to be very small probably in the nano coulombs, because 1 meter apart is not very far for the equation F=k q1 q2/rxr.
Q3,c
Comments,
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Q1,Yes, there can be an electric field at a point with no charge. But there will be no force from it untill a point with a charge is there. No, there will always be a field with a charge.
Q2,Well, in order to repel the charges would have to be like (both either positive or negative). This charge would have to be very small probably in the nano coulombs, because 1 meter apart is not very far for the equation F=k q1 q2/rxr.
Q3,c
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Q1,There can be an elect. field at a point where there is no charge b/c the elect. field is in a region aroung and including the charge. But there cannot be an electric charge with no elect. field b/c the charge must exist in order for the field to exist.
Q2,It the max. force you could hold was 5lbs. (49N), and holdin at a distance of 0.25m apart, a charge of greater than =1.31 e-5 C would be the maximum repulsion that you could overcome.
Q3,c
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Q1,yes; A point charge will create an electric field at that point and neighboring points as well. The neighboring points will have an electric field but not specifically a charge. yes; If a point charge is set in a place such that the electric fields of it and those causing forces aginst it cancel, there will be a charge at that point but no net electrical field.%09
Q2,Assume you hold them about1 meter apart and you are able to withstand a force of about 700N or approximately half your body weight. By Coulomb's law, Q is approximately 2.8 x 10(-4) C.
Q3,c
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Q1,If there is a charge at a point there will always be an electric field. An electric field must have a point were there is a charge to exist.
Q2,Let's say that I could hold on with 980 N, and the distance at which I am holding the balls apart is 1 m. I would us the equation q = sqrt(F*r^2/k). Which, with all the numbers plugged in and calculated, q = 3.3*10^-4 C.
Q3,d
Comments,I had some trouble in the homework with the Electric field calculations (22-7). I wasn't really even sure where to begin even after reading the chapter.
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Q1,yes there can be an electric field at a point where ther is no charge.a charge causes an electric field around it.
Q2,with r=1m and F= 250N Q= 1.66x10 -4
Q3,c
Comments,i find it confusing sometiimes to relate force to something i can handle how much force can i hold those tennis balls apart.
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Q1,first question: yes, if there is a charge somewhere near the point there will be an electric field at the point in question
Q2,d=1m Fmax=100N F=k(q^2)/r^2 k=9x10^9 q=1.05x10^(-4)C
Q3,c
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Q1,Yes, there may be an electric field caused by a charge neaby that is eminating an electric field. Yes, it is possible for two electric fields of opposite magnitude to cancel each other out. Thereby creating a point without an electric field.
Q2,Using the equation F=(kq^2)/(r^2) where F=500N, k=9.0*10^9, and r=.5m The charge can be upto 1.18*10^-4 coulombs or 118uC
Q3,c
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Q1,Yes there can be a field at a point where there is no charge. If there is an electron there is a field around it but the other points around it aren't charged. But I don't think that there can be a charge without a field of some sort.
Q2,I'm guessing that I could hold together about 200N (I don't know if that's even reasonable or not) and I choosing r to be a very small number (0.0000001m) since that if it were actually zero the math would fail. So my estimate is about 1.5*10^-11 C.
Q3,d
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Q1,An electrical field is emitted from a charged object uniformally and in all direction. So there is be a field all around the charge reguardless of the distance from the charge. ofcourse the farther away, the weaker the field. There cannot be a charge where there is no field, because a charge is going to emit a field, so if there is no field then there is no charge.
Q2,I have to assume that the balls are about 0.5 meters across and that an average human can sustain a force of about 100 lbs. or 4.45E2 N. then 4.45E2 = (k)(Q^2/(.5)^2). and k=9E9 then Q = 1.11E-4.
Q3,c
Comments,I think an insulator can be penetrated by an electrical field, although I didn't find it in the book. I think this because they make voltage testers that test to see if you have electricity at an outlet ib your house. Of course some of these have metal tips, but some have plastic tips on them. The plastic ones must recognize an electrical field when brought close to the circuit, then light up with the help of a AA battery inside them.
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Q1,There can be an electric field at a point where there is no charge. There must be a charge to create the field, but the charge does not have to be at that point, there is an electric field in the area around the charge. There cannot be a charge at a place where there is no electric field because the charge would create an electric field.
Q2,I'm not sure how many Newtons I can hang on to but I'm going to say about 100. If the distance between the balls is about .3 meters then 100 times .3^2 gives me 9. If I divide this by k I get 1E-9. Now I take the sguare root of this to find Q which is about 30nC.
Q3,c
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Q1,If there is no electric field at any point, then there cannot be a charge at that point. I think that the same is true that there can be no charge if there is no electric field.
Q2,I would have to find the forces exerted by the balls and estimate the force with which I could hold those two balls. F=K*(Q^2)/r^2 Let's assume that I can withstand a force of 200N holding the balls at a distnace of 20cm apart. The charge would be 2.9 X 10^-5. Any charge greater than that would force me to lose control of the balls.
Q3,d
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Q1,I hate to change my answer like this after I submitted and all but I guess there can be a charge with no electric field within the material of a conductor! This is Jennifer Green and I'm sorry for being a goofball-I promise to get my act at least somewhat together.
Q2,
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Q1,Yes there can be an electric field at a point where there is no charge, it is a consequence of the charge on body P only, if that is a body, well, I'm going to say that it is. But, there can be no force at a point where there is no charge. For the second question the answer is no. All charges exert an electric field.
Q2,I took 1 nC= 10^-9C and then found how many newtons that is which is about 90N. I then divided by gravity to find the number of kilograms, 9.8kg, and that equals about 20 pounds, so I'm sure that it can be a bit more but not too much more.
Q3,d
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Q1,Yes, if another body is producing a field, the field will influence the space around it. This field will be present at a given point even if it does not have a charge itself. No, since a positive or negative charge will both produce a field around an object(point).
Q2,The charge Q would have to be a value such that the force exerted by each ball on the other would be approximately 500N. This divided by gravity would be about 50kg (assuming I could hold 50kg in each hand). Thus the charge Q would be approximately 4 x 10^-4 c. (also assumed was arm length of 1.75m)
Q3,c
Comments,A little confusing when asked to give estimates. Should I assume things such as r being my out-stretched arm length. I tried to work this out on paper just using the formula, but was not able. So I started assuming things about this problem to come up with an estimate.
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Q1,There can be an electric field where there is no charge, because an electic field is highlighted by electic lines; in between these lines there may not be a charge, but there is a field. Anywhere there is a charge it will create a field around it, so I don't think there can be a charge without a field.
Q2,If it were as great a one C then it would be pretty hefty. Thus it would have to be a fraction of a Coulomb but larger than a micro Columb. Just a guestimation of course.
Q3,d
Comments,Its amazing that an electron is so small, but when they get together, they get alot done. Sure wish we acted more like electrons sometimes.
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Q1, There can be an electric field at a point where there is no charge because an outside source could create a field. There cannot be a charge where there is no field because an electric charge creates an electric field.
Q2, If a person could hold around 40 kilograms with there hands 1 meter apart then the value of Q on each ball would be 2*10^-4 coulombs.
Q3,d
Comments,
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Q1,Yes; Electric fields depend on the charge of source and distance. A second charge is not needed. For example, a electric field could permeate through a vacuum. By it's very nature, no charge could exist in that vacuum other than the source. Yes; If you have only one charge, that one charge will create an electric field around itself, but not including itself. Therefore, the charge would be at the center where there is no field.
Q2,Let's say I hold the balls 1 meter apart and I can only exert 450 N of force. The charge Q could be no more than about 2.25 e -4 C if I am able to hold onto them.
Q3,c
Comments,Before, in the past, I have at least seen the material once. So far this semester, things seem vaguely familiar. I hope things work out.
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Q1,Electric fields are areas around a charge so yes there can be an electric field at a point where there is no charge. E=kq/r^2. No there can not be a charge with no field. If there is a charge there is a field around the charge.
Q2,If my hands are approximately 20 cm apart and that I can hold approximately 100 lbs, then the value of Q would be approximately 2.2 x10^-5 C. (I'm doing this sans calculator.)
Q3,d
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Q1,There can be an electric field at a point of no charge from induced charge of a carged particle nearby. Since the field does not surround the source but another particle, there can be a charge with no field.
Q2,Supposing that I can reasonably hold 50lbs: 50/9.8=5.1N 5.1N=(9e9)qq/16 q=9.1e-9
Q3,c
Comments,Can you clarify the idea of electrical fields. The description in the book is difficult to visualize.
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Q1, There can be a charge where there is no field because is can be created by the air. There can not be an eletric field where there is no charge, like for example neutrons have no charge but the protons and neutrons that make the electric charges.
Q2, I beleive the maximum value Q can be for me is about 1000C.
Q3,c
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Q1,Yes, there can be an electric field at a point where there is no charge. Yes, there can also be a charge at a place where there is no field (although I'm not so sure about this one).
Q2,My general guess is 1*10^-6 C. This guess is based on my being able to hold only ten newtons (me being very weak, maybe?) and trying to hold them about 20cm apart. In addition, I'm being very vague in my math.
Q3,d
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Q1, There can be an electric field at points where there is no charge or mass for that matter. If there is a source with a charge, it generates an electric field. If the point has no charge and is much smaller that the distance, then an electric field, generated by the source object, is independent of the field point. There cannot be a charge without an electric field because a charge generates an electric field.
Q2, Human flesh is a good conductor, the balls would have a neutral if one were not wearing tennis shoes. Assuming that is not the case and that I could withstand 445 N (100lb), The maximum charge would be around 1 micro charge. F = (k * Q * Q) / square(r). Solving for Q gives Q = sqroot(F / k) * r = sqroot(445 / 8.988 * exp(9)) * 5 = 0.001112437284 C.
Q3,c
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Q1,There can be an electric field at a point where there is no charge because the formula for electric field E = k*(q/r^2) requires no field charge. The formula only need the charge of the source charge and the distance from the charge to a point in space. If a test charge is placed at a place where it does not experience a electric force, then there is no electric field present at that place caused by other charges. However, at the same time the charge causes an electric field.
Q2,The answer to this question depends on how strong or weak the person in question is and how far the t-balls are placed apart. Since I personally don't know how many newtons of force I am able to exert, I'm just going to assume that I can hold on to a force of, say 10 newtons, and the balls are 2 meters apart. Then, Q would equals 3.33e-4 coulomb.
Q3,c
Comments,
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Q1,When their is no charge in an area their still can be a electric field present. If their is no electric field present then their cannot be a charge in that area.
Q2,In this question the variables would depend on the persons ability. For me the max. would be around 50 kilograms for me and in this the radius at 1.0 x 10^9 gives a Q of about 52 C. This is only for this particular measurement.
Q3,d
Comments,I had a problem with number 2 i don't understand exactly how you wanted the question to be answered.
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Q1,Q1a) An electric field can act at a distance from the actual charge. This enables the electric field to be present even though the actual charge is not present at that point. Q1b) What generates an electric field is a charge. If a charge is present at a point, then an electric field must be present at that point. The only exception is within a conductor, where the electric field is always zero within the conducting material.
Q2,Q2a) Given that the tennis balls can be held at a distance of 47 inches and can be held with each arm at a force of 75lbs. The radius is 1.19 meters and the force is 333.62 newtons. The maximum charge that could be placed on each ball is 2.097x10-4 coulombs by calculation.
Q3,c
Comments,It has been displayed that electric force at small distances is far stronger than gravitational forces. Given the distance of electrons in close proximity within an atom, what keeps the electrons from crashing into the nucleus? What keeps the chaotic equlibrium that enables atoms from colapsing inward? Is it a nuclear force that repels electrons and attracts neutrons? What particles generate this force?
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Q1,Yes, the field can be caused by a body close by. No, without a field there is no place for a charge to occur.
Q2,I don't know.
Q3,d
Comments,
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Q1,Yes, the field can be caused by a body close by. No, without a field there is no place for a charge to occur.
Q2,I don't know.
Q3,d
Comments,
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Q1,1)Yes because an electric field doesn't depend on another charge other than the source charge... 2)I think yes because it you pick a point where the charge is located, then there is no field because the radius distance is 0..
Q2,For this question, two assumptions are made. A person can only exert a force of 600 Newtons on each side and the balls are one meter apart...By using the formula q=[(F * r^2)/k]^.5 then by substituting in, we get a value of a charge is 2.58e-4 C....
Q3,d
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Q1,Sure, there can be an electric field at a point where there is no charge. But there can not be a charge where there is no electric field. The existence of an electric field at a point where there is no charge just means that there is a charge relatively close by. But the field is a product of the charge, so without the charge there is no field.
Q2,Using Coulomb's law and estimating each hand can withstand about 44N at 1.3m apart. I get a charge on each ball of about +/- 9 X 10 -5C
Q3,c
Comments,
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Q1,No, the electric field is a product of a charge. The charge is the source for the electric field. Yes, there can be a charge where there is no field, because the charge in not dependant upon the field.
Q2,Assuming the maximum force that I can hold the balls is 700N (about 157 pounds) and I am holding them 1 meter apart, then the maximum charge Q could have would be 78 nC.
Q3,d
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Q1,By definition an electric field equals 'k', a constant, multiplied by a charge divided by the square of a displacement. If the charge equals zero, then the field equals zero. Conditions could produce a field of zero magnitude and direction if two like charges are placed linearly equidistant from a point.
Q2,For this problem I am estimating the maximum force I can hold to be 200 Newtons; in addition the distance I will try to maintain is 1 meter. Since force equals 'k', 8.988 x 10^9 N*m^2/C^2, multiplied by the charge squared (in this case) divided by the distance squared, the maximum charge I could handle would be 1.49 x10^-4 C.
Q3,d
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Q1,
Q2,
Comments,
Q1,Yes there can be an electric field at a point where there is no charge. There could be a charge where there is no field only if there is a 'cancelling' charge present.
Q2,force=k(Q1Q2)/r2 r^ sqrt(r2/9*10to the 9th(-i^)=Q
Q3,c
Comments,I still am confused about field and force. Had trouble last night connecting to iupui to do warm up -- slow when working to connect when I did the puzzle. Probably because of all the rookies?
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Q1,For part one, yes!, there can be an electric field where there is no charge. There must be some particle somewhere with a charge to produce that field, but there may not be a charge at the point being measured. There can be a charge on a particle but no field at that exact particle. This is the principle that a charge(body) cannot exert a net force on itself.I
Q2,I figure that I could hold back about 1kg or about 10 newtons for each ball. (maybe more or maybe I'm crazy) This would be a net force of 20 newtons measured from either ball. I'll assume a distance of 1 meter apart for ease of calculation(I can be lazy) 20N= 9x10(ninth)(qsquared)/1 according to my calcuations, the max charge on each ball would be 4.71x10(-5)
Q3,d
Comments,for number 3, the choices are almost correct. According to my reading and general knowledge, something can be a great insulator but there is not a PERFECT insulator. That was the basis of my answer. Please correct me if I am wrong.
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Q1,Yes, because an electric field is produced from a charged object and the field is present in the vicinity of that object. No, because a charged object produces an electric field, therefore, no field is present.
Q2,Based on working out at the gym, it is reasonable to expect be able to counter a 10lb (44.48N) force easily. Therefore, set F=44.48 Newtons My hands strecthed out in front of me are aproximately .3 meters apart. Therefore, set r=.3 meters Using F=k(q1*q2)/r^2 and solving for q, after plugging in the above, it would seem reasonable to expect: q=4.44*10^9 coulombs could be held in your hands. The sign of q of course would be opposite in order to satisfy the fact that the tennis balls are to repel each other.
Q3,c
Comments,I am particularly interested on the effects of electric fields and how they generate noise (extraneous signals) into instumentation systems and electronic control systems. For example, Data systems and electronic engine control systems that operate in the vincinity of high voltage ignition wires
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Q1,Yes, there can be an electric field at a point where there is no charge. Section 22-6. If there is no right or wrong answer, then I must say that I don't grasp the concept well enough yet to be able to answer the second question.
Q2,I think I would know how to answer this, but I've run out of time. I am going to do this differently than last semester, but I'm not on track yet.
Q3,c
Comments,
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